|
|
Post by lionheart305 on Dec 2, 2007 5:12:10 GMT -5
I've been given this problem to solve for college and it's really confusing me, anyone studying maths or further maths at college/uni should have some idea, any help on this would be greatly appreciated.
Problem
"Find all solutions in positive integers x, y, z to the simultaneous equations
x + y - z = 12
x² + y² - z² = 12"
Thanks very much 
|
|
|
|
Post by Hulkamaniac on Dec 2, 2007 5:30:16 GMT -5
The font color you chose makes it hard to read. The solution is very simple. Solve the first equation for x. Then substitute that answer for x in the second problem.
|
|
|
|
Post by ● kaneisdaman ● on Dec 2, 2007 5:41:22 GMT -5
I think you do it by rearranging the first equation so you gt x= and y= and then substitue it into the 2nd one. Then i think you have to use the elmination and/or substitution method of solving it further. That is all i can suggest, i haven't done college level maths.
|
|
|
|
Post by Hulkamaniac on Dec 2, 2007 5:52:43 GMT -5
This isn't really college level math. I did things like this in Algebra 2 in high school. I assume this is from an Intro to Algebra course?
|
|
|
|
Post by ● kaneisdaman ● on Dec 2, 2007 6:09:40 GMT -5
This isn't really college level math. I did things like this in Algebra 2 in high school. I assume this is from an Intro to Algebra course? I was thinking that because i remember in grade 10 we were doing senior high school maths which involved solving simultaneous equations with 3 unknowns. To solve it you basically need to do either or any of the following: -rearrange an equation -substitution method -elmination method -multiply an equation to make it eligible to be used in the elimination method |
|
bobski.
Main Eventer
...
Joined on: Feb 4, 2007 13:40:53 GMT -5
Posts: 1,751
|
Post by bobski. on Dec 2, 2007 8:53:03 GMT -5
the first one could be 3, 4 & 5
|
|
|
|
Post by nibz on Dec 2, 2007 9:02:34 GMT -5
the first one could be 3, 4 & 5 they have to be the same for both, don't they?  |
|
bobski.
Main Eventer
...
Joined on: Feb 4, 2007 13:40:53 GMT -5
Posts: 1,751
|
Post by bobski. on Dec 2, 2007 9:13:31 GMT -5
the first one could be 3, 4 & 5 they have to be the same for both, don't they? nope, I hate maths myself so I could be wrong |
|
